Estimated read time: Less than a minute
This archived news story is available only for your personal, non-commercial use. Information in the story may be outdated or superseded by additional information. Reading or replaying the story in its archived form does not constitute a republication of the story.
LOS ANGELES (AP) — The three top money winners in “Jeopardy!” history will vie for a share of $1.5 million in January.
ABC and the quiz show’s producer said Monday that Ken Jennings, Brad Rutter and James Holzhauer will compete in prime-time episodes on the network.
The first contestant to win three matches will receive $1 million. Each runner-up will take home $250,000.
Alex Trebek will host the contest, titled “Jeopardy! The Greatest of All Time” and debuting 8 p.m. Eastern on Jan. 7.
Rutter is the top all-time money winner with $4.7 million, followed by Jennings with $3.4 million and Holzhauer with $2.7 million.
In a statement, Trebek said the three have proved they qualify as the “greatest,” and now will compete to be “the best of the best.”
Copyright © The Associated Press. All rights reserved. This material may not be published, broadcast, rewritten or redistributed.
